3^2x-4(3^x-1)=-27

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Solution for 3^2x-4(3^x-1)=-27 equation: 



3^2x-4(3^x-1)=-27

We move all terms to the left:

3^2x-4(3^x-1)-(-27)=0

We add all the numbers together, and all the variables

3^2x-4(3^x-1)+27=0

We multiply parentheses

3^2x-12x+4+27=0

We add all the numbers together, and all the variables

-12x+3^2x+31=0

We move all terms containing x to the left, all other terms to the right

-12x+3^2x=-31

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